how 2 work out the gallonage of a particular size tank

[Andyneored5]

hey..


Whats the sum...

Thx

[Brian]

L x W x H in inches divided by 231

A gallon of water is 231 cubic inches

Andyneored5 wrote:
> hey..
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> Whats the sum...
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> Thx
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[Def Lizard]

Re: how 2 work out the gallonage of a particular size tank

Group: rec.aquaria.marine.reefs Date: Sun, Sep 28, 2003, 5:29pm (PDT+7)
From: (Brian)
L x W x H in inches divided by 231
A gallon of water is 231 cubic inches
Andyneored5 wrote:
hey..
Whats the sum...
Thx
************************************************** ***
Its L x W x H of the _inside_ measurements and height to the bottom of
the top frame (or if acrylic) 2 inches below the top (where the water
line would be) divided by 231. This would give you the capacity of an
_empty_ tank.
Better yet take outside L x W x H =8E=8F=F7 231 x .75 (this will give
you an _accurate_ gallonage capacity taking into account displacement by
objects in the tank [sand bed, rocks, heater, power heads, etc.] and the
water level is _not_ to the top of the tank!) Taking the LxWxH =F7 231
gives you the amount of water the tank would _displace_ if it were a
sealed box immersed in water and _not_ its water capacity! Ciao!


http://community.webtv.net/deflizard/doc
regards, John =

[Bob Phelps]

Check out ReefCentral.com -- they have calcultors for everything.
"Andyneored5" > wrote in message
...
> hey..
>
>
> Whats the sum...
>
> Thx
>
>
>
>

[Brian]

Def Lizard wrote:

>
> Re: how 2 work out the gallonage of a particular size tank
>
> Group: rec.aquaria.marine.reefs Date: Sun, Sep 28, 2003, 5:29pm (PDT+7)
> From: (Brian)
> L x W x H in inches divided by 231
> A gallon of water is 231 cubic inches
> Andyneored5 wrote:
> hey..
> Whats the sum...
> Thx
> ************************************************** ***
> Its L x W x H of the _inside_ measurements and height to the bottom of
> the top frame (or if acrylic) 2 inches below the top (where the water
> line would be) divided by 231. This would give you the capacity of an
> _empty_ tank.
> Better yet take outside L x W x H Ž?÷ 231 x .75 (this will give
> you an _accurate_ gallonage capacity taking into account displacement by
> objects in the tank [sand bed, rocks, heater, power heads, etc.] and the
> water level is _not_ to the top of the tank!) Taking the LxWxH ÷ 231
> gives you the amount of water the tank would _displace_ if it were a
> sealed box immersed in water and _not_ its water capacity! Ciao!

Sorry, you caught me in a mood :) Your *better yet* could be way off.
Temp glass is usually thinner then plate glass,1/2 inch glass or 1/4
inch, just right there you have a total of 1 inch. Having 10 lbs rock
compared to 100, 2 inch sand bed compared to 6 inch. There are to many
variables to just use .75. If this was to figure out an exact gallons
for medicine or for water changes I would drain the filled tank into 5
gallon buckets and then mark the side of the tank for how many inches it
drops for every 5 gallons.

Again don't take this as a flame. I am a recovering analytical myself.
The best advice someone gave me was: If a person asks you what time it
is, that is all they want to know. They don't need to know how the clock
works
>
>
> http://community.webtv.net/deflizard/doc
> regards, John
>