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134a Refrigerant



 
 
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  #991  
Old August 1st 05, 05:14 PM
Nathan W. Collier
external usenet poster
 
Posts: n/a
Default

"Stephen Cowell" > wrote in message
. ..
> You challenged Jeff
> to find a replacement for a head pressure control... I said
> you could just bypass the control if the ambient wasn't
> going to get low.


LIAR! you didnt say _anything_ until well AFTER i CLEARLY stated directly
TO YOU that the ambient was -30 and ive linked to it many times. you are a
LIAR. its right there for all to see
your lie.

> in fact was not part of the original challenge


see above link. it was INDEED part of the original challenge TO YOU and it
was given to you long before your pitiful google. :-)


> you refer to the 'credibility' of my links.


oh yeah, a link with "proudliberal" in the URL is credible. <rolling eyes>

youre a liar.....and id just bet youve been hearing that your entire
pathetic life.

--
Nathan W. Collier
http://InlineDiesel.com
http://7SlotGrille.com
http://UtilityOffRoad.com
http://BighornRefrigeration.com


Ads
  #992  
Old August 2nd 05, 01:20 AM
L.W.(ßill) Hughes III
external usenet poster
 
Posts: n/a
Default

Volume is measured in cubes, not squares, idiot!
God Bless America, ßill O|||||||O
http://www.billhughes.com/


Stephen Cowell wrote:
>
> Damn! that's funny! You found a sideways 8 in a simple
> volume calculation! How many times have you stuck the
> tanks and read the pumps? Tens of thousands? And never
> once (even with your advanced mathematics knowlege)
> did you ever get curious about why that tank chart was
> written like it was.
>
> Here's the first clue... the halfway point of the volume
> is the same, either standing up or laying down. This
> means that you know the half-volume from a simple
> (pi*(r^2)*L)/2 equation. That's half the area of the end
> circle times the length.
>
> One of the big things your math teacher couldn't
> get you to realize... in math, we seek *general*
> solutions... once you have the general solution,
> the rest of the examples are simply grinding
> through the equations. Here we seek the general
> solution to the volume of liquid in a partially-filled
> cylindrical tank, on its side... something you have
> had to do literally thousands of times in your life.
> Yet you have no clue... and continue to claim
> "I've gone through Calculus". If so, you went
> through it like corn through a goose.
> __
> Steve
> .

  #993  
Old August 3rd 05, 04:39 AM
Stephen Cowell
external usenet poster
 
Posts: n/a
Default


"Nathan W. Collier" > wrote in message
...
> "Stephen Cowell" > wrote in message
> . ..
> > You challenged Jeff
> > to find a replacement for a head pressure control... I said
> > you could just bypass the control if the ambient wasn't
> > going to get low.

>
> LIAR! you didnt say _anything_ until well AFTER i CLEARLY stated directly
> TO YOU that the ambient was -30 and ive linked to it many times. you are

a
> LIAR. its right there for all to

see
> your lie.


Watch him squeal! We all read it... you gave an example
of 'in a pinch' as 'such as on a rooftop in -30 degree weather'...
notice you didn't say that the challenge rules defined -30,
you were giving an example of 'in a pinch'. In fact, I believe
you're in a pinch now! You in no way defined a new challenge.

> > in fact was not part of the original challenge

>
> see above link. it was INDEED part of the original challenge TO YOU and

it
> was given to you long before your pitiful google. :-)


No... you gave an example of 'in a pinch'. This in no
way defined the exact terms of the challenge, and I can
think of several scenarios where you'd need to replace
the valve but the ambient was high. I also refer you to
the original challenge, where you had no such condition...
why do you attemp to put such a condition onto me,
when you didn't make the same condition to Jeff?
Says a lot about you, doesn't it? Says 'welch' to me...

> > you refer to the 'credibility' of my links.

>
> oh yeah, a link with "proudliberal" in the URL is credible. <rolling

eyes>

Logical fallacies... means your brain no workie too good.
Could be causing that eye rolling! See a doctor!

> youre a liar.....and id just bet youve been hearing that your entire
> pathetic life.


Keep squealing... makes me feel like I've accomplished
something here.

<>
you:
> more babble. i nailed you on it. i recognize my limitations and
> immediately own it. you lie, make excuses, and attempt to dazzle us with
> bull**** in hopes of hiding your blatent (sic) ignorance.


me:
You don't have a clue about your limitations... imagine you,
an HVAC tech, making pronouncements about atmospheric
science! That shows *extreme* hubris... you deserve what
you get.
</>

Limitations! Own them! Or lie about it... welch.
__
Steve
..





  #994  
Old August 3rd 05, 04:45 AM
Stephen Cowell
external usenet poster
 
Posts: n/a
Default


"Nathan W. Collier" > wrote in message
...
> "Stephen Cowell" > wrote in message
> ...
> >> yes, it is quite evident/obvious that you never let facts get in the

way
> > of
> >> your lies.

> >
> > Spinning Nate, got to go 'round

>
> yeah no ****, its all youre capable of. well, that and LYING when you

spin
> full circle and get hit in the face with your own bull****.


You can't give up... even though you are
digging the hole deeper and deeper.
We all can read... and remember. Just think...
this will live in the Google archives for thousands
of years! Own your limitations!


> > I met the challenge,

>
> LIAR. i asked youf or credible sources and you give me sites with
> "proudliberal" in the url. i know why you would stretch for such a lie

but
> nobody is falling for it.


Now you're very confused again... I can
understand, since your head's been spinning
a mile a minute since this started. Please
try to keep this straight... I'll remind you as
necessary. The 'challenge' involved the
head pressure control... the 'argument'
involved CFC's antagonism to the global
ozone layer. When I refer to 'challenge',
you should address the proper issue.
All clear?


> >> nope, just calling a liar a liar.

> >
> > You're just daubing the walls

>
> TRANSLATION --> "the truth hurts, nate.....please stop bitch-slapping me
> with it".


See what I mean... daubing the walls.

<>
you:
> more babble. i nailed you on it. i recognize my limitations and
> immediately own it. you lie, make excuses, and attempt to dazzle us with
> bull**** in hopes of hiding your blatent (sic) ignorance.


me:
You don't have a clue about your limitations... imagine you,
an HVAC tech, making pronouncements about atmospheric
science! That shows *extreme* hubris... you deserve what
you get.
</>

Limitations! Own them! Or lie about it...
__
Steve
..






  #995  
Old August 3rd 05, 04:58 AM
Stephen Cowell
external usenet poster
 
Posts: n/a
Default


"L.W. (ßill) Hughes III" > wrote in message
...
> Stephen Cowell wrote:
> >
> > Damn! that's funny! You found a sideways 8 in a simple
> > volume calculation! How many times have you stuck the
> > tanks and read the pumps? Tens of thousands? And never
> > once (even with your advanced mathematics knowlege)
> > did you ever get curious about why that tank chart was
> > written like it was.
> >
> > Here's the first clue... the halfway point of the volume
> > is the same, either standing up or laying down. This
> > means that you know the half-volume from a simple
> > (pi*(r^2)*L)/2 equation. That's half the area of the end
> > circle times the length.
> >
> > One of the big things your math teacher couldn't
> > get you to realize... in math, we seek *general*
> > solutions... once you have the general solution,
> > the rest of the examples are simply grinding
> > through the equations. Here we seek the general
> > solution to the volume of liquid in a partially-filled
> > cylindrical tank, on its side... something you have
> > had to do literally thousands of times in your life.
> > Yet you have no clue... and continue to claim
> > "I've gone through Calculus". If so, you went
> > through it like corn through a goose.


> Volume is measured in cubes, not squares, idiot!


You continue to top yourself! Are you not aware
of the formula for a regular cylinder? Do you not
agree that an area times a length gives you your
cubic dimension? What about good old Mr.
What'sHisName? Didn't he teach you about this?
You claimed to have 'gone through Calculus'!
Like corn through a goose, I replied... apropos.

Here's another hint... the liquid level forms
a chord across the end, parallel to a diameter
of the circular face. Draw a line from the
center of the circular face to the edge of the
tank where the liquid level is... a radius line.
It should all be clear now... if you can figure
out the area of a piece of 2D pie!
__
Steve
..




  #996  
Old August 3rd 05, 05:13 AM
Stephen Cowell
external usenet poster
 
Posts: n/a
Default


"Nathan W. Collier" > wrote in message
...
> "Stephen Cowell" > wrote in message
> ...
> > Well then... were you just forgetting, or
> > were you lying, when you wrote:
> > >"the only area i dont consider myself qualified on yet is ground
> > >source/geo thermal."


>
> lol reach all you want. if you think its a victory that im not doing cryo
> IN MONTANA then it just shows how pathetic you really are for any type of
> loose victory. :-)


No... I think it's a victory when I can point out your
silly mistakes... in your own avowed field of 'expertise'.
Not only a welch, but provincial, too!


> just what do YOU know about cryo? whats that, only what youve read

online?
> BUWAHAHA! :-)


'buwahaha'? Sounds like baby talk.

And you seem to have forgotten that I was
chief site tech at a radiotelescope for four years.
You see, I *did* cryo... lots of it. Dry helium,
two-stage piston refrigerators, thermocouple
vacuum sensors, recirculating oil compressors.
15 Kelvins, *that's* refrigeration.
__
Steve
..




  #997  
Old August 3rd 05, 05:16 AM
L.W.(ßill) Hughes III
external usenet poster
 
Posts: n/a
Default

Stevie, you bought the analogy of sticking a tank and said half full was
half the tank, true, but your were heading for if I dropped the stick
and it came up a quarter, that quarter, would be more like an eighth
tank.
God Bless America, ßill O|||||||O
http://www.billhughes.com/

Stephen Cowell wrote:
>
> You continue to top yourself! Are you not aware
> of the formula for a regular cylinder? Do you not
> agree that an area times a length gives you your
> cubic dimension? What about good old Mr.
> What'sHisName? Didn't he teach you about this?
> You claimed to have 'gone through Calculus'!
> Like corn through a goose, I replied... apropos.
>
> Here's another hint... the liquid level forms
> a chord across the end, parallel to a diameter
> of the circular face. Draw a line from the
> center of the circular face to the edge of the
> tank where the liquid level is... a radius line.
> It should all be clear now... if you can figure
> out the area of a piece of 2D pie!
> __
> Steve
> .

  #998  
Old August 3rd 05, 05:18 AM
Stephen Cowell
external usenet poster
 
Posts: n/a
Default


"Nathan W. Collier" > wrote in message
...
> "Stephen Cowell" > wrote in message
> ...
> >> exactly. i grossed over a grand today alone. what did you do, loser?

> > :-)
> >
> > Do you mean what did I "do", or what did I "earn"?

>
> both, as im quite sure that neither will amount to much above zero.
> > And which day, exactly, are you referring to?

>
> .....dumb ass cant read a date on a message header.


You made $1000 gross on Sunday? Well, I certainly
must admit that I didn't make a dime on Sunday.
Must put me into pretty hard company, for sure.
__
Steve
..


  #999  
Old August 3rd 05, 05:38 AM
L.W.(ßill) Hughes III
external usenet poster
 
Posts: n/a
Default

OK here's the equation for calculating the sticking volume of a
storage tank.
xx
x x
x------------x Liquid level which is variable,
x x can go up or down
x x
x x
x x
xx

Imagine the above is a circle. I know the diameter of the circle,
and I can measure from the top of the circle down to the liquid level.
How can I use this information to derive the amount of liquid in the
circle? I hope to make a formula I can use in a spreadsheet.

Thanks so much.


--------------------------------------------------------------------------------


Date: 3 Feb 1995 19:51:37 GMT
From: Dr. Math
Subject: Volume of partially filled cylinder on its side?

Hello there!

Thanks for writing to Dr. Math! You asked a good question.

Before we start, let's go over the "law of sines" (we'll be using
it shortly). Given a triangle ABC where A, B, and C are vertices,
the following relation holds:

sin A sin B sin C
-------- = ------- = -------
A B C

where sin A means sin of the angle at vertex A, and A (when it
appears in the denominator) is the length of the side of the
triangle opposite A.

Okay, now on to the problem. You did a nice job with your drawing
on the computer, so I'm not going to draw another picture. Instead,
you draw a picture on paper and label the following:

Call the distance from the top of the circle to the liquid level h.
Call the radius of the circle r.
(these are given quantities)

Now, draw in the center of the circle. Draw a line connecting the
center of the circle to the top of the circle. Then draw two more
lines from the center of the circle to the points where the liquid
level lines intersect the circle. Note that these lines are just radii,
so they have length r.

Now you have 3 triangles drawn, 2 of which are identical and make up the
third. Look at one of the small triangles. Call the angle at the center
angle z. One of the other angles is a 90 degree angle. Call the third
angle y. Now, note that the distance between the center of the circle
and the top of the circle is r (that's the definition of radius). We
already said that the distance between the top of the circle and the
liquid level was h, so that means the distance between the center of the
circle and the liquid level must be r-h, right? So, our small triangle
has a side of length r-h opposite the angle y, a side of length r
opposite the 90 degree angle, and a side of length x opposite angle z.
x is an unknown quantity we will need later on in the problem.

By the law of sines, we have the following relations:

r r-h x
----- = -------- = -----
* sin 90 sin y sin z

sin 90 = 1, so we have:

r-h
----- = r
sin y

Solve this equation for y to get:

y = arcsin [(r-h)/r]

Note also that z = 90 - y.

And, sin z = sin (90 - y) = cos y = cos [arcsin [(r-h)/r]] =
(1/r)Sqrt(2rh - h^2)

(this is by trig identities and stuff...if you have questions,
write back).

So, then equation * becomes:

rx
r = --------------
Sqrt (2rh - h^2)

So, x = Sqrt (2rh - h^2)

Now the problem is a lot easier. To find the area of the whole
circle, let's first consider the area contributed by the segment
we've been talking about that is of angle 2z from the center.

The area of this segment occupied by liquid is just the area of
the 2 small triangles. We know the base of each triangle is x
(see above) and the height is r-h. So, the total area contributed
by this segment is x(r-h).

Now consider the area outside of the segment. That is, we want
the area of a portion of the circle. If we measure z in degrees we
want the portion of the circle that takes up 360 - 2z degrees of the
circle. So, the fraction we are dealing with here is:

360 - 2z
--------
360

The area of the portion we want then is:

360 - 2z
-------- (Pi)r^2
360

Now add these two areas together and you are done. Thus, the total
area is going to be:

360 - 2(90 - arcsin [(r-h)/r])
------------------------------- (Pi)r^2 + (r-h)Sqrt (2rh - h^2)
360

God Bless America, ßill O|||||||O
http://www.billhughes.com/

Stephen Cowell wrote:
>
> You continue to top yourself! Are you not aware
> of the formula for a regular cylinder? Do you not
> agree that an area times a length gives you your
> cubic dimension? What about good old Mr.
> What'sHisName? Didn't he teach you about this?
> You claimed to have 'gone through Calculus'!
> Like corn through a goose, I replied... apropos.
>
> Here's another hint... the liquid level forms
> a chord across the end, parallel to a diameter
> of the circular face. Draw a line from the
> center of the circular face to the edge of the
> tank where the liquid level is... a radius line.
> It should all be clear now... if you can figure
> out the area of a piece of 2D pie!
> __
> Steve
> .

  #1000  
Old August 3rd 05, 06:33 AM
Nathan W. Collier
external usenet poster
 
Posts: n/a
Default

"Stephen Cowell" > wrote in message
. ..
> We all read it... you gave an example
> of 'in a pinch' as 'such as on a rooftop in -30 degree weather'...


you stupid stool. were it not for low ambient the HMC wouldnt be needed AT
ALL. its funny to watch you squirm and spin, hoping desperately that you
can convince use that you actually know something about refrigeration. LOL!
:-)


> No... you gave an example of 'in a pinch'. This in no
> way defined the exact terms of the challenge


lol bull****, liar. i CLEARLY stated -30 degrees. now squirm boy! :-)


> why do you attemp to put such a condition onto me,
> when you didn't make the same condition to Jeff?


being stump-stupid, you require further clarification. :-)


> Says a lot about you, doesn't it? Says 'welch' to me..


you pathetic little liar! i outlined it for you BEFORE you even knew what
an HMC was.


>> oh yeah, a link with "proudliberal" in the URL is credible. <rolling

> eyes>
>
> Logical fallacies


lol.....youre actually trying to suggest that a URL including "proudliberal"
is credible? BUWHAHAHA! :-)

--
Nathan W. Collier
http://InlineDiesel.com
http://7SlotGrille.com
http://UtilityOffRoad.com
http://BighornRefrigeration.com


 




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